## Question

The ionization energy of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by electromagnetic radiation of energy 12.1 eV. How many spectral lines will be emitter by the hydrogen atom?

### Solution

Two

When an electron in the ground state receives 12.1 eV of energy, it jumps to a level where its energy = 13.6 – 12.1 = 1.5 eV. This corresponds to the third excited state corresponding to *n* = 3. It can have two transitions, namely from *n* = 3 to *n* = 2 and from *n* = 3 to *n* = 1. Hence two spectral lines will be emitted.

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