Idea on Bayes' Theorem
I've got some insight on the Bayes' theorem. P(A|B) = P(B|A) * P(A) / P(B). Can't we switch the thing into: P(A|B) = P(A)*[P(B|A) / P(B)] . In that way, P(A|B) equals to the P(A) times ratio of P(B|A) / P(B). It means P(A|B) is just the ratio of P(B|A)...
Jul 2, 20253