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Observe that  is a set of natural numbers. If  then  cannot be finite, and it seems pretty obvious that almost all the elements in  are the same (they only disagree at a finite number of places after all). 

The bracketed remark doesn't appear to be true. Why can we not have  or ? Indeed, by the definition of an ultrafilter, we must have one of them in . Also, in the post, you use  for two different purposes, which makes the post slightly less clear.