John_Faben

The Weighted Majority Algorithm

Don - the "sleight of hand", as you put it is that (as I think has been said before) we're examining worst-case. We explicitly *are* allowing the string of 1s and 0s to be picked by an adversarial superintelligence who knows our strategy. Scott's algorithm only needs to sample 4 bits on average to answer the question *even when the universe it out to get him* - the deterministic version will need to sample exactly n/4+1.

Basically, Eliezer seems to be claiming that BPP = P (or possibly something stronger), which most people think is probably true, but, as has been said, no-one can prove. I for one accept his intuitive arguments as, I think, do most people who've thought about it, but proving this intuition rigorously is a major outstanding problem in computational complexity.

My supervior's intuitive argument for why you can never get anything from randomness is that in any particular case where randomness appears to help you can just pick a pseudo-random source which is "random enough" (presumably a formalisation of this intuition is what Scott's talking about when he says that BPP = P if "realy good pseudorandom generators exist").

The Truly Iterated Prisoner's Dilemma

I'm sure most people here are aware of Axelrod's classic "experiment" with an Iterated Prisoner's Dilemma tournament in which experts from around the world were invited to submit any strategy they liked, with the strategy which scored the highest over several rounds with each of the other strategies winning, and in which Tit for Tat came out top (Tit for Two Tats winning a later rerun. Axelrod's original experiment was fixed-horizon, and every single "nice" strategy (never defect first) that was entered finished above every single "greedy" strategy.

You should choose your strategy based the probability distribution you have for Clippy's strategy. If you think that, like you, he's read Axelrod, just choose Tit for Tat and you'll both be happy.

Timeless Identity

I get the feeling a lot of proponents of cryonics are a bit like those who criticize prediction markets, but refuse to bet on them. If you really believe that signing up for cryonics is so important, why aren't you being frozen *now*? Surely there are large numbers of branches in which your brain gets irretrievably destroyed tomorrow - if the reward for being frozen is so big, why wait?

Rationality Quotes 7

"Suppose we agree that shoplifting is morally objectionable behavior. Is it true that the only solution to shoplifting is violence or the threat of violence? I don't think so"

Well then you disagree with most of the rest of the world - at least in the UK, we tend to forcibly place shoplifters in prisons - if that's not violence, I don't know what is.

Don, if n is big enough then sure, I'm more than willing to play your game (assuming I get something out of it if I win).

My randomised algorithm will get the right answer within 4 tries in expectation. If I'm allowed to sample a thousand bits then the probability that it won't have found the answer by then is .75^1000 which I think is something like 10^-120. And this applies

even if you're allowed to choose the string after looking at my algorithm.If you play the game this way with your deterministic algorithm you will

alwaysneed to sample n/4 + 1 bits - I can put the ones where you'll never find them. If you don't like this game, fine don't do computational complexity, but there's nothing wrong with Scott's argument.Yes, we assume that you can't predict what random bits I will generate before I generate them, but that's pretty much what random means, so I don't see why it's such a big deal.