RD Chapter 14- Co-ordinate Geometry Ex-14.1 |
RD Chapter 14- Co-ordinate Geometry Ex-14.2 |
RD Chapter 14- Co-ordinate Geometry Ex-14.4 |
RD Chapter 14- Co-ordinate Geometry Ex-14.5 |

**Answer
1** :

The line segment joining the points A (-1,3) and B (4, -7) is divided into the ratio 3 : 4

Let P (x, y) divides AB in the ratio 3 : 4

Find the points of trisection of the line segment joining the points :

(i) (5, -6) and (-7, 5)

(ii) (3, -2) and (-3, -4)

(iii) (2, -2) and (-7, 4) [NCERT]

**Answer
2** :

(i) The line segment whose end points are A (5, -6) and B (-7,5) which is trisected at C and D

C divides it in the ratio 1 : 2

i.e., AC : CB = 1 : 2

**Answer
3** :
Let the vertices of the parallelogram ABCD be A (-2, -1), B (1, 0), C (4, 3) and D (1, 2) in which AC and BD are its diagonals which bisect each other at O

**Answer
4** :

Let the vertices of the quadrilateral ABCD be A (3, -2), B (4, 0), C (6, -3) and D (5, -5)

Now co-ordinates of the mid-point of AC

**Answer
5** :

Let P (9a – 2, -b) divides AB internally in the ratio 3 : 1.

By section formula,

=> 9a – 9 = 0

a = 1

**Answer
6** :
Since, (a, b) is the mid-point of line segment AB.

**Answer
7** :
Let the point P (2, y) divides the line segment joining the points A (-2, 2) and B (3, 7) in the ratio m1 : m2

**Answer
8** :

In ∆ABC, the vertices are A (-1, 3), B (1, -1) and C (5, 1)

D is the mid-point of BC

Co-ordinates of D will be [(1+5)/2 , (−1+1)/2]