Feb 03, 2012

34 comments

I wrote this post in the course of working through Vladimir Slepnev's A model of UDT with a halting oracle. This post contains some of the ideas of Slepnev's post, with all the proofs written out. The main formal difference is that while Slepnev's post is about programs with access to a halting oracle, the "decision agents" in this post are formulas in Peano arithmetic. They are generally uncomputable and do not reason under uncertainty.

These ideas are due to Vladimir Slepnev and Vladimir Nesov. (Please let me know if I should credit anyone else.) I'm pretty sure none of this is original material on my part. It is possible that I have misinterpreted Slepnev's post or introduced errors.

We are going to define a world function , a -ary function^{1} that outputs an ordered pair of payoff values. There are functions such that and for any . In fact is a function in the three variables and .

We are also going to define an agent function that outputs the symbol or . The argument is supposed to be the Gödel number of the world function, and is some sort of indexical information.

We want to define our agent such that

( denotes the Gödel number of . means that is provable in Peano arithmetic. represents the numeral for . I don't care what value has when isn't the Gödel number of an appropriate -ary function.)

There is some circularity in this tentative definition, because a formula standing for appears in the definition of itself. We get around this by using diagonalization. We'll describe how this works just this once: First define the function as follows:

This function can be defined by a formula. Then the diagonal lemma gives us a formula such that .

This is our (somewhat) rational decision agent. If it can prove it will do one thing, it does another; this is what Slepnev calls "playing chicken with the universe". If it can prove that is an optimal strategy, it chooses ; and otherwise it chooses .

First, a lemma about the causes and consequences of playing chicken:

**Lemma 1.** *For any ,*

( is a binary-valued function such that is true exactly when there is a proof of in Peano arithmetic. For brevity we write instead. is the proposition that Peano arithmetic, plus the axiom that Peano arithmetic is consistent, is a consistent theory.)

*Proof.* (1) By definition of ,

So

(2) By the principle of explosion,

(3) By the definition of ,

(4)

If we assume consistency of (which entails consistency of ), then parts (1) and (3) of Lemma 1 tell us that for any , and . So the agent never actually plays chicken.

Now let's see how our agent fares on a straightforward decision problem:

**Proposition 2.** *Let and s**uppose*

*Assume consistency of . Then if and only if .*

*Proof.* If we assume consistency of , then Lemma 1 tells us that the agent doesn't play chicken. So the agent will choose if and only if it determines that choosing is optimal.

We have

Suppose . Then clearly

So .

As for the converse: We have . If also

and , then . By Lemma 1(3) and consistency of , this cannot happen. So

Similarly, we have

for all . So

So the agent doesn't decide that is optimal, and .

Now let's see how fares on a symmetric Prisoner's Dilemma with itself:

**Proposition 3.** *Let*

*Then, assuming consistency of , we have .*

*Proof.*

(This proof uses Löb's theorem, and that makes it confusing. Vladimir Slepnev points out that Löb's theorem is not really necessary here; a simpler proof appears in the comments.)

Looking at the definition of , we see that

By Lemma 1, (1) and (3),

Similarly,

So

Applying Lemma 1(2) and (4),

By Löb's theorem,

By , we have

So, assuming , we conclude that .

The definition of treats the choices and differently; so it is worth checking that behaves correctly in the Prisoner's Dilemma when the effects of and are switched:

**Proposition 4.** *Let*

*Then, assuming consistency of , we have .*

A proof appears in the comments.

There are a number of questions one can explore with this formalism: What is the correct generalization of that can choose between actions, and not just two? How about infinitely many actions? What about theories other than Peano arithmetic? How do we accomodate payoffs that are real numbers? How do we make agents that can reason under uncertainty? How do we make agents that are computable algorithms rather than arithmetic formulas? How does fare on a Prisoner's Dilemma with asymmetric payoff matrix? In a two-person game where the payoff to player is independent of the behavior of , can deduce the behavior of ? What happens when we replace the third line of the definition of with

? What is a (good) definition of "decision problem"? Is there a theorem that says that our agent is, in a certain sense, optimal?

^{1}Every -ary function in this article is defined by a formula with free variables such that and . By a standard abuse of notation, when the name of a function like appears in a formula of arithmetic, what we really mean is the formula that defines it.